Optimal. Leaf size=79 \[ -\frac{\tan (e+f x) (d \sec (e+f x))^n F_1\left (n;\frac{1}{2}-m,\frac{1}{2};n+1;\sec (e+f x),-\sec (e+f x)\right )}{f n \sqrt{1-\sec (e+f x)} \sqrt{\sec (e+f x)+1}} \]
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Rubi [A] time = 0.0645752, antiderivative size = 79, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.087, Rules used = {3827, 133} \[ -\frac{\tan (e+f x) (d \sec (e+f x))^n F_1\left (n;\frac{1}{2}-m,\frac{1}{2};n+1;\sec (e+f x),-\sec (e+f x)\right )}{f n \sqrt{1-\sec (e+f x)} \sqrt{\sec (e+f x)+1}} \]
Antiderivative was successfully verified.
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Rule 3827
Rule 133
Rubi steps
\begin{align*} \int (1-\sec (e+f x))^m (d \sec (e+f x))^n \, dx &=-\frac{(d \tan (e+f x)) \operatorname{Subst}\left (\int \frac{(1-x)^{-\frac{1}{2}+m} (d x)^{-1+n}}{\sqrt{1+x}} \, dx,x,\sec (e+f x)\right )}{f \sqrt{1-\sec (e+f x)} \sqrt{1+\sec (e+f x)}}\\ &=-\frac{F_1\left (n;\frac{1}{2}-m,\frac{1}{2};1+n;\sec (e+f x),-\sec (e+f x)\right ) (d \sec (e+f x))^n \tan (e+f x)}{f n \sqrt{1-\sec (e+f x)} \sqrt{1+\sec (e+f x)}}\\ \end{align*}
Mathematica [B] time = 0.279261, size = 257, normalized size = 3.25 \[ \frac{(2 m+3) \sin (e+f x) (1-\sec (e+f x))^m (d \sec (e+f x))^n F_1\left (m+\frac{1}{2};m+n,1-n;m+\frac{3}{2};\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )}{f (2 m+1) \left (2 \tan ^2\left (\frac{1}{2} (e+f x)\right ) \left ((n-1) F_1\left (m+\frac{3}{2};m+n,2-n;m+\frac{5}{2};\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )+(m+n) F_1\left (m+\frac{3}{2};m+n+1,1-n;m+\frac{5}{2};\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )\right )+(2 m+3) F_1\left (m+\frac{1}{2};m+n,1-n;m+\frac{3}{2};\tan ^2\left (\frac{1}{2} (e+f x)\right ),-\tan ^2\left (\frac{1}{2} (e+f x)\right )\right )\right )} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.734, size = 0, normalized size = 0. \begin{align*} \int \left ( 1-\sec \left ( fx+e \right ) \right ) ^{m} \left ( d\sec \left ( fx+e \right ) \right ) ^{n}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (d \sec \left (f x + e\right )\right )^{n}{\left (-\sec \left (f x + e\right ) + 1\right )}^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\left (d \sec \left (f x + e\right )\right )^{n}{\left (-\sec \left (f x + e\right ) + 1\right )}^{m}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (d \sec{\left (e + f x \right )}\right )^{n} \left (1 - \sec{\left (e + f x \right )}\right )^{m}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (d \sec \left (f x + e\right )\right )^{n}{\left (-\sec \left (f x + e\right ) + 1\right )}^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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